Question

Помогите пж решить задание по алгебре. Номер 593

Answer 1

$y12 = y1 + 11d = \ a)- 9.9 + 11 times 1.8 = - 9.9 + 19.8 = 9.9 \ y20 =y1 + 19d \ y20 = - 9.9 + 19 times 1.8 = \ - 9.9 + 34.2 = 24.3 \ b)y12 = 10 + 11 times ( - 0.2) = 7.8 \ y20 = 10 + 19 times ( - 0.2) =6 .2$