Question

Помогите плиииз.
4cos²45°+tg²30°

Answer 1

4cos²45°+tg²30°=4*(√2/2)²+(√3/3)²=

4*2/4+3/9=2+1/3=2 1/3

Answer 2

$4Cos^{2}45^{o} +tg^{2}30^{o}=4*(frac{sqrt{2} }{2})^{2}+(frac{1}{sqrt{3} })^{2}=4*frac{1}{2}+frac{1}{3}=2+frac{1}{3}=2frac{1}{3}$