Question

14-9x+x² решите пж
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Answer 1

${x}^{2} - 9x + 14 = 0$
а=1, b=-9, c=14

${b}^{2} - 4ac = ( - 9)^{2} - 4 times 1 times 14 = 81 - 56 =25$
$x1 = frac{ - b + sqrt{d} }{2a} = frac{ 9 + 5}{2} = frac{14}{2} = 7$
$x2 = frac{9 - 5}{2} = frac{4}{2} = 2$
Ответ: Х1=7; Х2=2