Question

Помогите пожалуйста решить:
1.(4+n)^2
2.(10p^3-7q)(10p^3+7q)
3.(2-a)^3
4.18-12bc+2b^2c^2
5.(2b+3a)^3

Answer 1

1)(4+n)^2 = 16+8n+n^2 = n^2++16
2)(10p^3-7q)(10p^3+7q) = (10p^3)^2-(7q)^2 = 100p^6-49q^2
3)(2-a)^3 = 8-12a+6a^2-a^3 = -a^3+6a^2-12a+8
4)18-12bc+2b^2c^2 = 2(9-6bc+b^2c^2) = 2(3-bc)^2
5)(2b+3a)^3 = (2b)^3+3×(2b)^2×3a+3×2b×(3a)^2+(3a)^3 = 8b^3+3×4b^2×3a+3×2b×9a^2+27a^3 = 8b^3+36ab^2+54a^2b+27a^3