Question

y=sqrt(2x-3)/cosx/2 найти производную

Answer 1

$y=frac{sqrt{2x-4}}{cosfrac{x}{2}}\\y'=frac{frac{1}{2sqrt{2x-4}}cdot 2cdot cosfrac{x}{2}-sqrt{2x-4}cdot (-sinfrac{x}{2})cdot frac{1}{2}}{cos&2frac{x}{2}}=frac{2, cosfrac{x}{2}+(2x-4)cdot sinfrac{x}{2}}{2sqrt{2x-4}cdot cos^2frac{x}{2}}=frac{cosfrac{x}{2}+(x-2)cdot sinfrac{x}{2}}{sqrt{2x-4}cdot cos^2frac{x}{2}}$