Question

(3х+1)^2-(3х-2)(2+3х=17

Answer 1

$(3x+1)^2-(3x-2)(2+3x)=17\\9x^2+6x+1-(9x^2-4)=17\\9x^2+6x+1-9x^2+4=17\\6x+5=17\\6x=12\\boxed{x=2}$