Question

(2x-1)^2
(4+а)^2
(2а+3b)^2
(x^3-3)^3

Answer 1

(2x-1)² = 4х²-4х+1

(4+а)² = 16+8а+а²

(2а+3b)² = 4a²+12ab+9b²

(x³-3)³ = x⁹-9x⁶+27x-27

Answer 2

гш863384494949493933

Answer 3

30th. .

Answer 4

$1)(2x - 1 {)}^{2} = (2x {)}^{2} - 2 times 2x times 1 + {1}^{2} = \ 4 {x}^{2} - 4x + 1 \ 2)(4 + a {)}^{2} = {4}^{2} + 2 times 4 times a + {a}^{2} = \ 16 + 8a + {a}^{2} \ (2a + 3b {)}^{2} = (2a {)}^{2} + 2 times 2a times 3b + (3b {)}^{2} = \ 4 {a}^{2} + 12ab + 9 {b}^{2} \ ( {x}^{3} - 3 {)}^{3} = ( {x}^{3} {)}^{3} - 3 times ( {x}^{3} {)}^{2} times 3 - 3 times {x}^{3} times 9 - 27 = \ {x}^{9} + 9 {x}^{6} - 27 {x}^{3} - 27$

Answer 5

В последнем уравнении напутала со знаками, надо бы поправить

Answer 6

хорошо