Question

Решите пожалуйста))) ​

Answer 1

$1)(5sqrt{18}+sqrt{18})*sqrt{2}= 6sqrt{18}*sqrt{2}=6sqrt{18*2}=6sqrt{36}=6*6=36$

$2)(sqrt{27}-sqrt{12}):sqrt{3}=(sqrt{27:3}-sqrt{12:3})=sqrt{9}-sqrt{4}=3-2=1$

$3)(sqrt{3}+6)(2-sqrt{3})=2sqrt{3}+12-(sqrt{3})^2-6sqrt{3}=12-3-4sqrt{3}=9-4sqrt{3}$

$4)(sqrt{m}+3)(sqrt{m}-3)=(sqrt{m})^2-3^2=m-9$

$5)(sqrt{13}-sqrt{5})^2=(sqrt{13})^2-2*sqrt{13}*sqrt{5}+(sqrt{5})^2=\\=13-2sqrt{65}+5=18-2sqrt{65}=2*(9-sqrt{65})$

$6)(5sqrt{2}+sqrt{6})^2=(25*sqrt{2})^2+2*5sqrt{2}*sqrt{6}+(sqrt{6})^2=\\=50+10sqrt{12}+6=56+10*2sqrt{3}=56+20sqrt{3}=4*(14+5sqrt{3})$

$7)(sqrt{3}+1)(3-sqrt{3}+1)=(sqrt{3}+1)(4-sqrt{3})=\\=4sqrt{3}+4-(sqrt{3})^2-sqrt{3}=3sqrt{3}+4-3=3sqrt{3}+1$