Question

Помогите с дз. Дам 21 баллов! Не пишите чушь.

Answer 1

1) $frac{y-2}{y-5}+frac{y+2}{2y+1}=frac{(y-2)(y+2)}{(y-5)(2y+1)};\  frac{(y-2)(2y+1)+(y+2)(y-5)}{(y-5)(2y+1)}-frac{(y-2)(y+2)}{(y-5)(2y+1)}=0;\frac{2y^2+y-4y-2+y^2+2y-5y-10-y^2-4}{(y-5)(2y+1)}=0;\frac{(2+1-1)y^2+(1-4+2-5)y+(-2-10-4)}{(y-5)(2y+1)} =0;$

$frac{1y^2-3y-8}{(y-5)(2y+1)}=0;D=9+32=41\ y=frac{3бsqrt{41} }{2}$ Ответ.

2) $frac{2y-23}{y+3} -frac{y+1}{y-7} = frac{(2y-23)(y+1)}{(y+3)(y-7)} ;\frac{(2y-23)(y-7)-(y+1)(y+3)-(2y-23)(y+1)}{(y+3)(y-7)}=0;\frac{(2y-23)(y-7-(y+1))-(y+1)(y+3)}{(y+3)(y-7)}=0;\frac{-12y+138-y^2-4y-3}{(y+3)(y-7)}=0;\frac{y^2+16y-135}{(y+3)(y-7)}=0;D=256+540= 796;$

$y=frac{-16б2sqrt{199} }{2} =-8бsqrt{199}$ Ответ.