Question

ПОМОГИТЕ С АЛГЕБРОЙ РЕШИТЬ УРАВНЕНИЯ СРОЧНО

Answer 1

${x}^{2} + 5x = 0 \ x times (x + 5) = 0 \ x = 0 \ x = - 5$
$2 {x}^{2} - 3x = 0 \ x times (2x - 3) = 0 \ x = 0 \ 2x - 3 = 0 \ x 1= 0 \ x 2= frac{3}{2} = 1.5$
$- 7 {x}^{2} + 4x = 0 \ - x times (7x - 4) = 0 \ - x = 0 \ 7x - 4 = 0 \ x1 = 0 \ x2 = frac{4}{7}$