Question

Решите пожалуста. Можно только ответы.24 бАлла.

Answer 1

2.

$1)(c - 1)(c + 1) \ 2) {(x - 2)}^{2} \ 3)(5y - 2)(5y + 2) \ 4) {(6a - 5b)}^{2}$

3.

${x}^{2} - 9 - ( {x}^{2} - 8x + 16) = \ {x}^{2} - 9 - {x}^{2} + 8x - 16 = \ - 25 + 8x$

4.

$(5x - 1)(x + 2) + 3(x - 4)(x + 4) \ = 2 {(2x + 3)}^{2} - 8 \ {5x}^{2} + 10x - x - 2 + 3 {x}^{2} - 48 = \ 2( {4x}^{2} + 12x + 9) - 8$

${8x}^{2} + 9x - 50 = 8 {x}^{2} + 24x + 18 \ - 8 \ 8 {x}^{2} + 9x -50 - 8 {x}^{2} - 24x \ - 10 = 0$

5.

$(3a - 1) {}^{2} - (a + 2) {}^{2} = \ {9a}^{2} - 6a + 1 - {a}^{2} - 4a - 4 = \ 8 {a}^{2} - 10a - 3$

6.

$( {a}^{2} - 36)(36 + {a}^{2} ) - ( {a}^{4} + 4a \ + 4) = {a}^{4} - 1296 - {a}^{4} - 4a - 4 = \ - 1300 - 4a$

$( {a}^{2} - 36)(36 + {a}^{2} ) - ( {a}^{4} - {36a}^{2} \ + 324) = {a}^{4} - 1296 - {a}^{4} + 36 {a}^{2} \ - 324 = - 1620 + 36 {a}^{2}$

$- 1620 + 36 times ( - frac{1}{6} ) {}^{2} \ = - 1620 + 36 times frac{1}{36} = - 1619$

7 не знаю