Question

ХЭЭЭЭЭЭЭЛПпппппппппппп

Answer 1

$begin{cases}b_1-b_2=36\b_3-b_4=4end{cases}Rightarrowbegin{cases}b_1-b_1q=36\b_1q^2-b_1q^3=4end{cases}Rightarrowbegin{cases}b_1=frac{36}{1-q}\frac{36q^2}{1-q}-frac{36q^3}{1-q}=4end{cases}\frac{36q^2}{1-q}-frac{36q^3}{1-q}=4\frac{36q^2(1-q)}{1-q}=4\36q^2=4\q^2=frac4{36}\q=pmfrac26=pmfrac13\begin{cases}b_1=27\q=-frac13end{cases}quadquadquad u/|uquadquadquadbegin{cases}b_1=54\q=frac13end{cases}\\27,;-9,;3,;-1\u/|u\54,;18,;6,;2$