Question

16^log₄(5-√5)+4^log₂(√5+5)

Answer 1

Смотри.....................

Answer 2

СССпосибо

Answer 3

$16^{log_4(5-sqrt5)}+4^{log_2(sqrt5+5)}=(4^2)^{log_4(5-sqrt5)}+(2^2)^{log_2(sqrt5+5)}=\\=4^{2log_4(5-sqrt5)}+2^{2log_2(sqrt5+5)}=4^{log_4(5-sqrt5)^2}+2^{log_2(sqrt5+5)^2}=\\=(5-sqrt5)^2+(sqrt5-5)^2=(25-10sqrt5+5)+(5+10sqrt5+25)=\\=30+30=60$