Question

6 класс. Самостоятельная. СРОЧНО!!

Answer 1

$1.\a);-4,1-(-1,6+2,32)=-4,1-0,72=-4,82\b);-1frac57+left(-2frac13-1frac27right)=-1frac{15}{21}-2frac7{21}-1frac6{21}=-4frac{28}{21}=-5frac7{21}=-5frac13\c);(4,6-5,9)+1frac13-left(2frac25-frac23right)=-1,3+1frac13-left(2frac6{15}-frac{10}{15}right)=-1frac3{10}+1frac13-1frac{11}{15}=\=-1frac9{30}+1frac{10}{30}-1frac{22}{30}=-1frac{21}{30}=-1frac{7}{10}$

$2.\a);-(-b+1,2)+3,2=b-1,2+3,2=b+2\b);(-2,8+n)-n=-2,8+n-n=-2,8\c);(4,3-y)-(5,8+y)=4,3-y-5,8-y=-1,5-2y$

$3.\a);4,5-(m+2,8)=4,5-m-2,8=1,7-m=1,7-(-2,2)=1,7+2,2=3,9\b);-n+(3,8-n)+4,3=-n+3,8-n+4,3=8,1-2n=8,1-2cdot0,8=8,1-1,6=6,5$

$4.;1frac23-(y+2)=-2frac13\y+2=1frac23+2frac13\y+2=4y=4-2\y=2\Pi POBEPKA:;1frac23-(2+2)=1frac23-4=-2frac13\\5.;b+b+a-(b-a)=b+b+a-b+a=b+2a$

Answer 2

№1.

а) - 4,1-(-1,6+2,32)= -4,1+1,6-2,32=-4,82

б)

$- 1frac{5}{7} + ( - 2 frac{1}{3} - 1 frac{2}{7}) = \ - 1 frac{5}{7} - 2 frac{1}{3} - 1 frac{2}{7} = - 5 frac{1}{3}$

в)

$(4.6 - 5.9) + 1frac{1}{3} - (2 frac{2}{5} - frac{2}{3} ) = \ - 1.3 + 1 frac{1}{3} - 2 frac{2}{5} + frac{2}{3} = \ frac{23}{5} - frac{59}{10} + frac{4}{3} - frac{26}{15} = - 1 frac{7}{10}$

№2

a)-(-b+1,2)+3,2=b-1,2+3,2=b+2

b)(-2.8+n)-n= - 2,8+n-n= -2,8

c)(4,3-y)-(5.8+y)=4,3-y-5,8-y= -1,5-2y

№3

а)4,5-(m+2,8)=4,5-m-2,8=1,7-m

Если m=-2,2,то 1,7-(-2,2)=3,9

б) -n+(3.8-n)+4,3=-n+3.8-n+4,3=8,1-2n
Если n=0,8,то 8,1-1,6=6,5

№4

$1 frac{2}{3} - (y + 2) = - 2 frac{1}{3} \ 1 frac{2}{3} - y - 2 = - 2frac{1}{3} \ - y = - 2 frac{1}{3} - 1 frac{2}{3} + 2 \ - y = - frac{7}{3} + frac{1}{3} \ y = 2$

Проверка: 1 2/3-(2+2)=-2 1/3

1 2/3-4= - 2 1/3

-2 1/3=-2 1/3

№5

b+b+a-(b-a)=b+2a

2b+a-b+a=b+2a

b+2a=b+2a