Question

2x
${2x}^{2} + 4x - 3 = 0$
​

Answer 1

2х² + 4х - 3 = 0
D = 16 - 4 * 2 * (-3) = 16 + 24 = 40
√D = √40

x1 = (-4 + √40)/4 =
$frac{ - 2 + sqrt{10} }{2}$
x2 = (-4-√40)/4 =
$frac{ - 2 - sqrt{10} }{2}$