Question

Решите уравнение

(6-х)³-х²(16-х)=2х²+116

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Answer 1

$tt (6-x)^3-x^2(16-x)=2x^2+116\216-108x+18x^2-x^3-16x^2+x^3=2x^2+116\2x^2-108x +216=2x^2+116\2x^2-2x^2-108x=116-216\-108x=-100\x=cfrac{-100}{-108}= cfrac{25}{27}$