Question

прошу 2,6............​

Answer 1

Пошаговое объяснение:

$frac{1}{3}sqrt{18}+2sqrt{2}= frac{1}{3}sqrt{9*2}+2sqrt{2}=frac{1}{3}sqrt{9}*sqrt{2}+2sqrt{2}=\\=frac{1}{3}*3*sqrt{2}+2sqrt{2}=sqrt{2}+2sqrt{2}=3sqrt{2}$

$3sqrt{48}-sqrt{75}+frac{1}{7}sqrt{147}=3sqrt{16*3}-sqrt{25*3}+frac{1}{7}sqrt{49*3}=\\=3sqrt{16}*sqrt{3}-sqrt{25}*sqrt{3}+frac{1}{7}sqrt{49}*sqrt{3}=3*4sqrt{3}-5sqrt{3}+frac{1}{7}*7sqrt{3}=\\=12sqrt{3}-5sqrt{3} +sqrt{3}=7sqrt{3}+sqrt{3}=8sqrt{3}$