Question

с р о ч н о
комплексные числа​

Answer 1

$xin R; ,; ; yin R\\z_1=x-frac{y^2}{i}-4+5i; ; ,; ; z_2=y^2+1-3xi\\z_1=xi+y^2i-4i-5=(x+y^2-4), i-5\\z_2=(y^2+1)-3x, i=-z_1; ; to ; ; left { {{y^2+1=4-x-y^2} atop {-3x=5}} right. ; left { {{2y^2=3+5/3} atop {x=-5/3}} right. \\left { {{y^2=frac{14}{3}} atop {x=-frac{5}{3}}} right. ; ; left { {{y=pm sqrt{frac{14}{3}}} atop {x=-frac{5}{3}}} right.\\Otvet:; ; (-frac{5}{3}, ,, sqrt{frac{14}{3}}); ; ,; ; (-frac{5}{3}, ,, -sqrt{frac{14}{3}}); .$