Question

Решите пожалуйста
${x}^{2} - 6 + 5 = 0$
${2x}^{2} - 5x + 4 = 0$
${3x}^{2} - 6x + 2 = 0$

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Answer 1

${x}^{2} - 6x + 5 = 0 \ x_{1} + x_{2} = 6 \ x_{1} times x_{2} = 5 \ x_{1} = 1 \ x_{2} = 5 \ Ответ: (1; : 5) \ \ </p><p>{2x}^{2} - 5x + 4 = 0 \ D=25 - 4 times 2 times 4 = - 7</p><p> \ \ Ответ: действ.корней : : нет \ \ {3x}^{2} - 6x + 2 = 0 \ D = 36 - 4 times 3 times 2 = 12 \ x_{1} = frac{6 - sqrt{12} }{2 times 3} = frac{6 - 2 sqrt{3} }{6} = \ = frac{3 - sqrt{3} }{3} \ x_{2} = frac{3 + sqrt{3} }{3} \ Ответ: (frac{3 - sqrt{3} }{3}; : frac{3 + sqrt{3} }{3})$