Question

(4b-9)²-(3b+8)² памагити

Answer 1

16b^2-72b+81-

-(9b^2+48b+64)=

7b^2-120b+17.

Answer 2

$(4b-9)^{2}-(3b+8)^{2} = \ = ((4b-9)-(3b+8)) times ((4b-9) + (3b+8)) = \ = (4b-9 - 3b - 8) times (4b-9 + 3b+8) = \ = (b-17) (7b-1)$=7b^{2}-b-119b+17=\ =7b^{2}-120b+17