Question

(3-b)(3+b)(9+b²)+(4+b²)²

Answer 1

$(3-b)(3+b)(9+b^2)+(4+b^2)^2=(9-b^2)(9+b^2)+(4+b^2)^2=81-b^4+16+8b^2+b^4=97+8b^2$