Question

(3x+1)(4x-5)=(3x+1)(2x-1) решите уравнение. Не пишите ответ напишите как это решать​

Answer 1

$(3x + 1)(4x - 5) = (3x + 1)(2x - 1) \ 12 {x}^{2} - 15x + 4x - 5 = 6 {x}^{2} - 3x + 2x - 1 \ 12 {x}^{2} - 11x - 5 = 6 {x}^{2} - x - 1 \ 12 {x}^{2} - 11x - 5 - 6 {x}^{2} + x + 1 = 0 \ 6 {x}^{2} - 10x - 4 = 0 \ 3 {x}^{2} - 5x - 2 = 0 \ x times (3x + 1) - 2(3x + 1) = 0 \ (3x + 1)(x - 2) = 0 \ 3x + 1 = 0 \ x - 2 = 0 \ x1 = - frac{1}{3} \ x 2 = 2$