Question

решите уравнения

0,7x4-x3=0
0,5x3-72x=0
x3+4x=5x2
3x3-x2+18x-6=0
2x4-18x2=5x3-45x
3y2-2y=2y3-3

Answer 1

0,7х4-х3=0
2,8-х3=0
-3х=-2,8
-х=-2,8:3=$- frac{14}{5}$:$frac{3}{1}$=$- frac{14}{5}$х$frac{1}{3}$
-х=$-frac{14}{15}$
х=$frac{14}{15}$

0,5х3-72х=0
1,5-72х=0
-72х=-1,5
-х=$frac{3}{2} : (-frac{72}{1} )= frac{3}{2}$х$-frac{1}{72}$
х=$frac{1}{48}$