Question

CpoчHo gаю 30 балов помогите!!!!!!

Answer 1

log(3)(log²(0,5)x+3log(0,5)x+5)=2
1)
x>0
log(0,5)x=t

t²+3t+5>0

D=9-20=-11<0

t€(-oo;+oo)

2)t²+3t+5=3²

t²+3t-4=0

D=9+16=25

t=(-3±5)/
t1=-4;t2=1
log(0,5)x=-4;x=16
log(0,5)x=1
x=0,5
oTBeT 0,5;1