Question

(8x-1)(2x-3)-(4x-1)в квадрате=38

Answer 1

(8x-1)(2x-3)-(4x-1)^2=38

-2(9-1)=2*19

2-18=38

-18х=36

-18х=-18*(-2)

х=-36:18

х= -2

ответ : -2