Question

Пожалуйста,срочно надо

Answer 1

$a);f(x)=2x^6-x^4+3x^3+18\f'(x)=16x^5-4x^3+9x^2\\b);y=x^2(x^5+2x^2-7x)=x^7+2x^4-7x^3\y'=7x^6+8x^3-21x^2\\c);f(x)=frac6x\f'(x)=-frac6{x^2}\f'(x)=-6\\d);f(x)=frac{7-2x^2}{7+2x^2}\f'(x)=frac{-4x(7+2x^2)-4x(7-2x^2)}{(7+2x^2)^2}=frac{-28x-8x^3-28x+8x^3}{(7+2x^2)^2}=-frac{56x}{(7+2x^2)^2}\f'(0)=0\f'(1)=-frac{56}{(7+2)^2}=-frac{56}{81}$

$e);f(x)=(x^2-4x)(4x^2-x)=4x^4-17x^3+4x^2\f'(x)=16x^3-51x^2+8x\\f);f(x)=frac{4x^2-17x+4}{x-4}\f'(x)=frac{(4x-17)(x-4)-(4x^2-17x+4)}{(x-4)^2}=frac{4x^2-33x+68-4x^2+17x-4}{(x-4)^2}=frac{64-16x}{(x-4)^2}=\=frac{-16(x-4)}{(x-4)^2}=-frac{16}{x-4}$