Question

√2 (√50-√32)
помогите пж))

Answer 1

$displasytyle tt sqrt2(sqrt{50}-sqrt{32})=sqrt{50cdot2}-sqrt{32cdot2}=sqrt{100}-sqrt{64}=10-8=boxed{2}$

Answer 2

большое спасибо))

Answer 3

$sqrt{2}(sqrt{50}-sqrt{32})=sqrt{2}*sqrt{50}-sqrt{2}*sqrt{32}=sqrt{100}-sqrt{64}=sqrt{10^{2} }-sqrt{8^{2} }=10-8=2$