Question

Очень срочно, помогите пожалуйста..(

Answer 1

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Answer 2

№5

1)

$4sqrt{5}=sqrt{16}sqrt{5}=sqrt{16*5}=sqrt{80}\3sqrt{8}=sqrt{9}sqrt{8}=sqrt{9*5}=sqrt{72}\80>72; sqrt{80}>sqrt{72}\4sqrt{5}>3sqrt{8}$

2)

$7sqrt{frac{2}{7}}=sqrt{49}sqrt{frac{2}{7}}=sqrt{frac{49*2}{7}}=sqrt{14}\frac{1}{2}sqrt{56}=sqrt{frac{1}{4}}sqrt{56}=sqrt{frac{56}{4}}=sqrt{14}\7sqrt{frac{2}{7}}=frac{1}{2}sqrt{56}$

№6

1)

$frac{x-25}{sqrt{x}-5}=frac{(sqrt{x})^2-5^2}{sqrt{x}-5}=frac{(sqrt{x}-5)(sqrt{x}+5)}{sqrt{x}-5} =sqrt{x} +5$

2)

$frac{6+5sqrt{6}}{sqrt{6}}=frac{sqrt{6}*sqrt{6}+5*sqrt{6}}{sqrt{6}}=frac{sqrt{6}*(sqrt{6}+5)}{sqrt{6}}=sqrt{6}+5$

3)

$frac{c+14sqrt{c}+49}{c-49}=frac{(sqrt{c})^2+2*7*sqrt{c}+7^2}{(sqrt{c})^2-7^2}=frac{(sqrt{c}+7)^2}{(sqrt{c}-7)(sqrt{c}+7)}=frac{sqrt{c}+7}{sqrt{c}-7}$