Question

помогите срочно решить!!!​

Answer 1

Найдём Rц=R1+( R2*R3,4/R2+R3,4)=2+(3*5.5/3+5.5)=2+1.941=3.941om,

I1=E/R+r=12/ 3.941+0.5=2.702a,, U1=I1*R1=2.702*2om=5.404в, ΔE=2.702*0.5om=1.351в,,  U2=U3,4=12в-(5.404в+1.351в)=5.245в,,

I2=5.245/3om=1.748a,,   I3,4=5.245/5.5om=0.953a,

I1=I2 + I3.4⇒2.702a=2.701a