Question

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Answer 1

$frac{sqrt{648}}{18}=sqrt{2}$

$frac{sqrt{675}}{15}=sqrt{3}$

$frac{sqrt{875}}{5}=sqrt{35}$

$frac{sqrt{216}}{6}=sqrt{6}$

$frac{sqrt{98}}{7}=sqrt{2}$

$frac{sqrt{432}}{12}=sqrt{3}$

$frac{sqrt{726}}{11}=sqrt{6}$

$frac{sqrt{675}}{15}=sqrt{3}$

$frac{sqrt{875}}{5}=sqrt{35}$

$2^{12} *(2^{3})^{-5} =2^{12}*2^{-15}=2^{-3}=1/8=0,125$

$3^{-9} *(3^{4})^{3} =3^{-9}*3^{12}=3^{3}=27$

$frac{sqrt{512}}{8}=sqrt{8}=2sqrt{2}$

$frac{sqrt{98}}{7}=sqrt{2}$

$frac{sqrt{432}}{12}=sqrt{3}$

$frac{sqrt{726}}{11}=sqrt{6}$

Answer 2

Спасибо