Question

решить уравнение -2000x2+1200x+1500=0

Answer 1

-2000x²+1200x+1500=0

-20x²+12x+15=0

Δ=12²-4*(-20)*15

Δ=144+1200

Δ=1344

√Δ=8√21

 

x₁=(-12-8√21)/(2*(-20))

x₁=(-12-8√21)/(-40)

x₁=(3+2√21)/10

 

x₂=(-12+8√21)/(2*(-20))

x₂=(-12+8√21)/(-40)

x₂=(3-2√21)/10

 

 

Answer 2

 -2000x²+1200x+1500=0

20х²-12х-15=0

D=144+15*20*4=1344

√D=√1344=8√21

x₁=(12+8√21)/40=(3+2√21)/10

x₂=(12-8√21)/40=(3-2√21)/10