Question

Сократить одну дробь

Answer 1

(x^(1/3) - 2x^(1/6) · y^(1/6) + y^(1/3))/(x^(1/2) · y^(1/3) - x^(1/3) · y^(1/2) =

= (x^1/6 - y^(1/6))²/(x^(1/3) · y^(1/3) ·(x^/1/6) - y^(1/6))) =

= (x^/1/6) - y^(1/6))/(x^(1/3) · y^(1/3))