Question

1/х+7+1/х-3=0
Найдите корень уравнения.

Answer 1

$frac{x - 3 + x + 7} {(x + 7)(x - 3)} = 0 \ frac{2x + 4}{(x + 7)(x - 3)} = 0 \ x = - 7 \ x = 3 \ 2x + 4 = 0 \ x = - 2$

$[tex] frac{x - 3 + x + 7} {(x + 7)(x - 3)} = 0 \ frac{2x + 4}{(x + 7)(x - 3)} = 0 \ x = - 7 \ x = 3 \ 2x + 4 = 0 \ x = - 2$[/tex]

Answer 2

1/х+7+1/х-3=0

х-3+х7

_______= 0 это дробь

(х+7)(х+3)

2х+4

-----------------------=0

$(x + 7)(x - 3) \ x = - 7 \ x = 3 \ \ 2x + 4 = 0$

2х+4=0

х=-2