Question

(sin8a/1+cos8a) * (cos 4a/1+cos4a) * (sin4a/1-cos4a) упростить выражение
Помогите пожалуйста

Answer 1

$frac{Sin8alpha }{1+Cos8alpha }*frac{Cos4alpha }{1+Cos4alpha }*frac{Sin4alpha }{1-Cos4alpha }=frac{Sin8alpha }{1+Cos8alpha }*frac{0,5Sin8alpha }{1-Cos^{2} 4alpha }=frac{0,5Sin^{2}8alpha}{(1+Cos8alpha)Sin^{2}4alpha}=frac{0,5Sin^{2}8alpha}{2Cos^{2}4alpha*Sin^{2}4alpha}=frac{0,5Sin^{2}8alpha}{0,5Sin^{2}8alpha}=1$