Question

sin74°×ctg53°+cos74°​

Answer 1

$sin74^ocdot cgt53^o+cos74^o=$

$sin(2cdot37^o)cdotfrac{cos53^o}{sin 53^o}+cos(2cdot37^o)=$

$2sin37^o cos37^ocdotfrac{cos(90^o-37^o)}{sin(90^o-37^o)}+1-2sin^237^o=$

$2sin37^o cos37^ocdotfrac{sin37^o}{cos37^o}+1-2sin^237^o=$

$2sin^237^o-2sin^237^o=1$

Answer 2

Спасибо огромное

Answer 3

:)