Question

помогите, мне сейчас надо​

Answer 1

$2a)y=frac{1}{3}x^{2}+3\\f(3)=frac{1}{3}*3^{2}+3=frac{1}{3}*9+3=3+3=6\\f(3)=6\\f(-5)=frac{1}{3}*(-5)^{2}+3=frac{1}{3}*25+3=frac{25}{3}+3=8frac{1}{3}+3=11frac{1}{3}\\f(-5)=11frac{1}{3} \\2b)(k;6)\\6=frac{1}{3}k^{2}+3|*3\\18=k^{2} +9\\k^{2}=9\\k_{1}=-3\\k_{2}=3$