Question

вычислите: 3sin p/2+4cos2p/3+6sin13p/6​

Answer 1

$3sin(frac{pi }{2} )+4cos(frac{2pi }{3} )+6sin(frac{13pi }{6} )= 3*1+4(-frac{1}{2} )+6*frac{1}{2}= 3-2+3= 4$