Question

log^22(вторая двойка твнизу)-4log2x=12

Answer 1

$log(2)^{2} - 4 log(2x) = 12 \ x > 0 \ - 4 log(2x) = 12 - log(2)^{2} \ log(2x) = frac{12 - log(2)^{2} }{ - 4} \ log(2x) = - 3 + frac{ { log(2) }^{2} }{4} \ 2x = 10^{ - 3 + frac{ { log(2) }^{2} }{4} } \ x = frac{10^{ - 3 + frac{ { log(2) }^{2} }{4} } }{2}$