Question

tg x - √3tg x +1= √3

Answer 1

tgx - √3•tgx + 1 = √3

tg•(1 - √3) + (1 - √3) = 0

(tgx + 1)(1 - √3) = 0

tgx + 1 = 0

tgx = - 1

x = (-π/4) + πn, n ∈ Z

ОТВЕТ: (-π/4) + πn, n ∈ Z