Question

решите
$2 times sqrt{4 + sqrt{7} }$

Answer 1

$2 times sqrt{4 + sqrt{7} } =sqrt{4(4 + sqrt{7} )} = sqrt{16 +4sqrt{7} } = sqrt{14+4sqrt{7} +2} =\sqrt{(sqrt{14})^2+2 sqrt{28} +(sqrt2)^2} =sqrt{(sqrt{14}+sqrt2)^2}=sqrt{14}+sqrt2$

Answer 2

спасибо огромное

Answer 3

:)