Question

sin 45 cos 45 tg 60 - cos 30 tg 45

Answer 1

$sin 45^{circ} cdot cos 45^{circ}cdot text {tg } 60^{circ}- cos 30^{circ}cdot text {tg } 45^{circ} = \ =frac{sqrt{2}}{2} cdot frac{sqrt{2}}{2} cdot sqrt{3} - frac{sqrt{3}}{2} cdot 1=frac{2}{4} cdot sqrt{3} - frac{sqrt{3}}{2}=\=frac{sqrt{3}}{2}-frac{sqrt{3}}{2}=0$

Ответ: 0