Question

(2m+3)^2-(3-2m)^2=

(2b+3)^2-(5+b)^2=

(5a+4)^2-25a^2=

СРОЧНО ПОЖАЛУСТА

Answer 1

$(2m+3)^2-(3-2m)^2=\=4m^2+12m+9-4m^2+12m-9=\=24m$

$(2b+3)^2-(5+b)^2=\=4b^2+12b+9-b^2-10b-25=\=3b^2+2b-16=\=(b-2)(3b+8)$

$(5a+4)^2-25a^2=\=25a^2+40a+16-25a^2=\=40a+16=\=8(5a+2)$