Question

(a²-3)³-(a²-4)(a²+4)-a²(a4-10a²+ 27)+27=16

Answer 1

(a²-3)³-(a²-4)(a²+4)-a²(a4-10a²+ 27)+27=16

$a^{6}$ + 0 -27 - $4a^{3}$ = 0

$a^{6}$ - $4a^{3}$ - 27 = 0

$t^{2}$ - 4t - 27 = 0

t = 2 + $sqrt{31}$

t = 2 - $sqrt{31}$

$a^{3}$ = 2 + $sqrt{31}$

$a^{3}$ = 2 - $sqrt{31}$

Ответ: a = $sqrt[3]{2+sqrt{31}}$

a = $sqrt[3]{2-sqrt{31}}$