Question

СРОЧНО!!! 40 баллов за ОДИН ПРИМЕР!!!
((корень2)-sinA-cosA)/(sinA-cosA)

Answer 1

$frac{sqrt2-sina-cosa}{sina-cosa}=frac{sqrt2-(sina+cosa)}{sina-cosa}=\\\star ; sina+cosa=sina+sin(frac{pi}{2}-a)=2, sinfrac{pi}{4}cdot cos(a-frac{pi}{4})=sqrt2, cos(x-frac{pi }{4}); star \\star ; sina-cosa=sina-sin(frac{pi}{2}-a)=2sin(a-frac{pi}{4})cdot cosfrac{pi}{4}=sqrt2, sin(a-frac{pi}{4}); star \\\=frac{sqrt2-sqrt2, sin(a-frac{pi}{4})}{sqrt2, cos(a-frac{pi}{4})}=frac{1-sin(a-frac{pi}{4})}{cos(a-frac{pi}{4})}=frac{1}{cos(a-frac{pi}{4})}-frac{sin(a-frac{pi}{4})}{cos(a-frac{pi}{4})}=\\=frac{1}{cos(a-frac{pi}{4})}-tg(a-frac{pi}{4})=sec(a-frac{pi}{4})-tg(a-frac{pi}{4}); ;\\star ; ; frac{1}{cosx}=secx; ; star \\\P.S.\\star ; sin(a-frac{pi}{4})=cos(frac{pi}{2}-(a-frac{pi}{4}))= cos(frac{pi}{2}+frac{pi}{4}-a)=cos(frac{3pi}{4}-a); star \\frac{1-sin(a-frac{pi}{4})}{cos(a-frac{pi}{4})}=frac{1-cos(frac{3pi}{4}-a)}{cos(a-frac{pi}{4})}=frac{2sin^2(frac{3pi}{8}-frac{a}{2})}{cos(a-frac{pi}{4})}$

Answer 2

Помогите пожалуйста с графиком
https://znanija.com/task/31837166