Question

Помогите с 12 номером

Answer 1

$y=frac{4}{3}, xsqrt{x}-10x+6; ; ,quad ODZ:; xgeq 0\\y=frac{4}{3}cdot x^{frac{3}{2}}-10x+6\\y'=frac{4}{3}cdot frac{3}{2}cdot x^{frac{1}{2}}-10=2sqrt{x}-10=0; ; ,; ; sqrt{x}=5; ; ,; ; x=25\\znaki; y'(x):; ; ; [, 0, ]---[, 25, ]++++++\\x_{min}=25; ,; ; y_{min}=y(25)=frac{3}{4}cdot 25^{3/2}-10cdot 25+6=frac{3}{4}cdot 5^3-250+6=-150,25\\min; v; tochke; ; A(25;, -150,25)$