Question

4. Решите уравнение:
1) 5x³ - 5x = 0; 3) x³ - 3x² - 4x + 12 = 0.
2) 64x³ - 16x² + x = 0;

Answer 1

$1)5x( {x}^{2} - 1) = 0 \ 5x = 0 \ x = 0 \ {x}^{2} - 1 = 0 \ {x}^{2} = 1$

$x1 = 1 \ x2 = - 1$

$3) {x}^{2} (x - 3) - 4(x - 3) = 0 \ x - 3 = 0 \ x = 3 \ {x}^{2} - 4 = 0$

${x}^{2} = 4 \ x1 = 2 \ x2 = - 2$

$2)x(64 {x}^{2} - 16x + 1) = 0 \ x(8x - 1) {}^{2} = 0 \ x = 0$

$8x - 1 = 0 \8 x = 0 + 1 = 1 \ x = frac{1}{8}$