Question

решите уравнение: tg (П/8-2x/3)=√3

Answer 1

на фото....................

Answer 2

$tg(frac{pi }{8}-frac{2x}{3})=sqrt{3}\frac{pi }{8}-frac{2x}{3}=frac{pi }{3}+ pi k, k in Z\\frac{2}{3}x=frac{pi }{8}-frac{pi }{3}-pi k , k in Z\\frac{2}{3}x=-frac{5pi }{24} -pi k , k in Z (*frac{3}{2})\ \x=-frac{15pi }{48} -frac{3pi }{2}k, k in Z \\x=-frac{5pi }{16} -frac{3pi }{2}k , k in Z$