Question

9^3/2 +27^2/3 - (1/16)^3/4

Answer 1

$9^{frac{3}{2} }+27^{frac{2}{3} }-(frac{1}{16})^{frac{3}{4} }=(3^{2})^{frac{3}{2} }+(3^{3})^{frac{2}{3} }-((frac{1}{2})^{4})^{frac{3}{4}}=3^{3}+3^{2}-(frac{1}{2})^{3}=27+9-0,125=35,875$