Question

Разложи на множители (u+13v)^2−(13u+v)^2

Answer 1

$(u+13v)^2-(13u+v)^2 =(u+13v+13u+v)(u+13v-13u-v)=\\(14u+14v)(-12u+12v)=14(u+v)cdot12(v-u)=168(u+v)(v-u)$