Question

Найти y’ и y’’

y2 = x + ln(y/x)

Answer 1

$y^2=x+lnfrac{y}{x}\\2yy'=1+frac{x}{y}cdot frac{1}{x}cdot y'\\y'(2y-frac{1}{y})=1\\y'cdot frac{2y^2-1}{y} =1\\y'=frac{y}{2y^2-1}$